Wednesday, October 3, 2001

Announcements: Chapter 6:  Momentum and Collisions

Newton's Second Law (as Newton defined it):  F = dp/dt

Momentum (linear) is defined as:  p = mv

If no external forces act on a system, momentum is conserved (constant): pi = pf
A 2-dimensional collision can be analyzed along x and y axes.

Impulse = F*t = change in momentum

In an inelastic collision, momentum is conserved, but kinetic energy is not.
In an elastic collision, both momentum and kinetic energy are conserved.
Most collisions are partially elastic/inelastic.

Demos:

Example Problem:  If you jump up in the air to a height, h, how much force does the ground exert on you when you land?  What do you need to know?
Solution:  You need to know the distance your body moves as you bend your knees:  x ~ 0.5 m
From conservation of energy, your speed just before touching the ground is:  v = sqrt(2gh).
From here, you can take two different approaches to solve this problem:
Conservation of energy:  work done by ground = change in kinetic energy
    F*x = 0.5mv2
    F = mv2/(2x)

Conservation of momentum:  impulse = change in momentum
    F*t = mv
    x = 0.5at2  and v2 = 2ax, so t = 2x/v
    so  F = mv2/(2x)   - same as above for conserv. of energy

Minute paper: Assignments: